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14 February, 08:06

A and B play a game in which they alternately toss a pair of dice. The one who is first to get a total of 7 wins the game. Find the probability that (a) the one who tosses first wins the game

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  1. 14 February, 09:20
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    Answer: the probability that the first toss wins is:

    P = 1/6 or 0.1667

    Step-by-step explanation:

    A die has six sides (that is 6 outcome per die)

    For a pair of dice:

    The Total number of possible outcomes = 6 * 6 = 36

    The possible outcomes of 7 is:

    (1,6), (2,5), (3,4), (4,3), (5,2), (6,1)

    = 6

    The probability P of getting 7 is:

    P = number of possible outcomes of 7/total number of possible outcomes

    P = 6/36 = 1/6

    The probability that the first toss wins

    P = 1/6 or 0.1667
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