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23 May, 18:29

The prices of two ratios are in the ratio x:y

When the prices are both increased by £20 the ratio becomes 5:2

When the prices are both reduced by £5 the ratio becomes 5:1

Express the ratio x:y in its lowest terms

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Answers (2)
  1. 23 May, 20:25
    0
    4:1

    Step-by-step explanation:

    x+20 : y+20 = 5 : 2

    (x+20) / (y+20) = 5/2

    2 (x+20) = 5 (y+20)

    2x+40 = 5y+100

    2x = 5y+60 (1)

    x-5 : y-5 = 5:1

    (x-5) / (y-5) = 5/1

    x-5 = 5 (y-5)

    x-5 = 5y-25

    x = 5y-20 (2)

    Solve (1) & (2) simultaneously,

    2 (5y-20) = 5y+60

    10y-40 = 5y+60

    5y = 100

    y = 20

    x = 5y-20

    x = 5 (20) - 20 = 100-20

    x = 80

    x:y

    80:20

    4:1
  2. 23 May, 21:23
    0
    Answer: x:y = 2:5

    Step-by-step explanation:

    Given : The prices of two radios are in the ratio x:y

    When the prices are both increased by £20, the ratio becomes 5:2

    Then,

    When the prices are both reduced by £5, the ratio becomes 5:1

    Then,

    Subtract (2) from (1), we get

    Put this value in (2), we get

    Now, the ratio of x:y=

    Dividing 4 from both the numerator and denominator, we get

    x:y = = 2:5

    Credit: JeanaShupp
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