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6 May, 20:38

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered 3 from the second bag? Wh

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  1. 6 May, 22:13
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    Complete question:

    Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

    1 2 3 4 5 6

    Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered three from the second bag?

    Answer: 1/36

    Step-by-step explanation:

    Number of tiles in each bag = 6

    Probability of drawing tile numbered 2 from the first bag and the tile numbered 3 from the second

    Probability of drawing number 2 from first bag:

    P (numbered 2) = (required outcome / possible outcome)

    P (numbered 2) = 1/6

    Probability of drawing number 2 from first bag:

    P (numbered 3) = 1/6

    Since they are independent events:

    P (drawing 2 from bag one and 3 from bag 2):

    1/6 * 1/6 = 1/36
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