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11 February, 01:39

A standard 52-card deck consists of 4 suits (hearts, diamonds, clubs, and spades). Each suit has 13 cards: 10 are pip cards (numbered 1, or ace, 2 through 10) and 3 are face cards (jack, queen, and king). You randomly draw a card then place it back. If it is a pip card, you keep the deck as is. If it is a face card, you eliminate all the pip cards. Then, you draw a new card. What is the probability you draw the queen of hearts in the end?

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  1. 11 February, 03:06
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    P[ draw the queen of hearts in the end ] = 0.034

    Step-by-step explanation:

    total number of cards = 52

    number of face cards = 12 (each suit has 3 face cards)

    number of pip cards = 40 (each suit has 10 pip cards)

    P[ Drawing a face card ] = 12/52

    If a pip card is drawn in the first trial, you keep the deck as is.

    P[ draw the queen of hearts in the end | a pip card is drawn in the first trial ] = 1/52 (only 1 queen of hearts in one deck)

    P[ Drawing a pip card ] = 40/52

    If it is a face card, you eliminate all the pip cards.

    Number of remaining cards = 12 (all face cards)

    P[ draw the queen of hearts in the end | a face card is drawn in the first trial ] = 1/12 (only 1 queen of hearts in one deck)

    P[ draw the queen of hearts in the end ] = P[ draw the queen of hearts in the end | a face card is drawn in the first trial ]*P[ Drawing a pip card ] + P[ draw the queen of hearts in the end | a pip card is drawn in the first trial ]*P[ Drawing a face card ]

    P[ draw the queen of hearts in the end ] = (1/12) * (12/52) + (1/52) * (40/52)

    P[ draw the queen of hearts in the end ] = (1/52) + (40/2704)

    P[ draw the queen of hearts in the end ] = (52 + 40) / 2704

    P[ draw the queen of hearts in the end ] = 92/2704

    P[ draw the queen of hearts in the end ] = 0.034
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