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11 August, 07:02

A quadratic rule for a particular parabola is of the form y = ax^2 + bx. The parabola passes through with the coordinates (-1, 4) and one of its x-axis intercepts is 6. Find the value of a and b.

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  1. 11 August, 10:35
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    y = (4/7) x² - (24/7) (x)

    Step-by-step explanation:

    4 = a (-1) ² + b (-1)

    4 = a - b

    0 = a (6) ² + b (6)

    36a + 6b = 0

    b = - 6a

    4 = a - (-6a)

    7a = 4

    a = 4/7

    b = - 24/7

    y = (4/7) x² - (24/7) (x)
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