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10 February, 03:34

Which equation will solve the following word problem? One small pitcher and one large pitcher can hold 12 cups of water. If the large pitcher is twice the size of the small pitcher, how much does the small pitcher hold? 2S + S = 12 2S = 12/S 2S - S = 12 S = 12/2S

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  1. 10 February, 07:08
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    Option (1).

    Step-by-step explanation:

    Amount of water hold by both the pitchers (Large + small) = 12 cups

    Let the small pitcher holds the water = S cups

    If the water hold by the large pitcher is twice the size of the small pitcher, then the amount of water hold by large pitcher = 2S

    Total amount water hold by both = S + 2S

    Equation for this situation will be,

    S + 2S = 12

    Therefore, Option (1) will be the answer.
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