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23 January, 05:17

Given the domain - 4,0,5 what is the range for 12x+6y=24

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Answers (2)
  1. 23 January, 06:43
    0
    The range is - 6, 4, 12.

    Step-by-step explanation:

    If the domain is - 4,0,5, x can only be - 4 or 0 or 5.

    Substitute each of these x-values into the equation 12x+6y=24. Then isolate to find the possible values of x.

    Sub x for - 4

    12x+6y=24

    12 (-4) + 6y=24

    -48+6y=24

    6y = 72

    y = 12

    Sub x for 0

    12x+6y=24

    12 (0) + 6y=24

    6y = 24

    y = 4

    Sub x for 5

    12x+6y=24

    12 (5) + 6y=24

    60 + 6y = 24

    6y = - 36

    y = - 6

    The possible values of y are - 6, 4,12 which is the range.

    In set notation: R = y
  2. 23 January, 07:06
    0
    Range for - 4,0,5 are 12,4,-6. (-4, 12), (0,4), (5,-6)
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