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13 September, 06:04

How do I find out if this is an infinite solution

4 (x-2) + 7 = 4x - 1

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  1. 13 September, 09:15
    0
    x = all real numbers, infinite solutions

    Step-by-step explanation:

    4 (x-2) + 7 = 4x - 1

    Distribute

    4x - 8+7 = 4x-1

    Combine like terms

    4x - 1 = 4x-1

    Subtract 4x from each side

    4x-1 - 4x = 4x-1-4x

    -1 = - 1

    This is always true so there are infinite solutions for x
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