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28 October, 21:07

A small rocket is launched from a height of 6 feet off of the ground at an initial upward velocity of 64 feet per second. Its

height is given by the equation h = -162t^2 + 64t + 6, where h is the height of the rocket in feet and t is the time since

liftoff in seconds. At what time is the rocket 54 feet in the air?

A. 1 second

B. 3 seconds

C. 1 second and 3 seconds

D. none of the above

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Answers (1)
  1. 28 October, 22:17
    0
    Answer:did u listen to ur teacher

    Step-by-step explanation:

    im not answering that until u listen
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