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13 March, 07:36

If 4 people are selected from a group of 6 married couples, what is the probability that none of them would be married to each other?

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  1. 13 March, 08:53
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    16/33

    Step-by-step explanation:

    12C4 (total possible outcomes) = 495

    Since there are 6 married couples there must be 6*[2C2*10C2]=270

    must subtracted 15 since when there are 2 couples in a group would have doubled 270-15=255

    the no of groupings with no married couples 495-255 = 240

    probability=no of favourable outcomes / no of possible outcome

    probability=240/495 = 16/33
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