car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 12 ft/sec2. How long before the car stops? Round your answer to one decimal place.

66.7 feet

Step-by-step explanation:

v² = u² + 2as

0² = 40² + 2 (-12) (so

1600 = 24s

s = 66⅔ or 66.7

It will take 3.3 seconds before the car stops

Step-by-step explanation:

Initial Velocity, u = 40 ft/sec

Final Velocity, v = 0

acceleration, a = - 12 ft/sec² (deceleration)

Formula = > v = u + at

Substitute for each parameter

0 = 40 + (-12) t

0 = 40 - 12t

12t = 40

t = 40 / 12

t = 3.3 sec