Ask Question
5 December, 23:10

Andrew invested $3,100 in an account paying an interest rate of 2.1% compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest dollar, would be in the account after 16 years?

+4
Answers (1)
  1. 6 December, 02:16
    0
    Answer: $4338 would be in the account after 16 years.

    Step-by-step explanation:

    The formula for continuously compounded interest is

    A = P x e (r x t)

    Where

    A represents the future value of the investment after t years.

    P represents the present value or initial amount invested

    r represents the interest rate

    t represents the time in years for which the investment was made.

    e is the mathematical constant approximated as 2.7183.

    From the information given,

    P = $3100

    r = 2.1% = 2.1/100 = 0.021

    t = 16 years

    Therefore,

    A = 3100 x 2.7183^ (0.021 x 16)

    A = 3100 x 2.7183^ (0.336)

    A = $4338 to the nearest dollar
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Andrew invested $3,100 in an account paying an interest rate of 2.1% compounded continuously. Assuming no deposits or withdrawals are made, ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers