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17 June, 07:10

Factor the following quadratic expression completely : 64x^2

- 121

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Answers (2)
  1. 17 June, 07:54
    0
    Since both terms are perfect squares, factor using the difference of squares formula, a2-b2 = (a+b) (a-b) where a=8x and b=11

    .

    (8x+11) (8x-11)
  2. 17 June, 10:36
    0
    64x^2-121

    Rewrite 64x^2 as 8x^2

    Rewrite 121 as 11^2

    Now you have 8x^2-11^2

    Use the difference of squares formula, a^2 - b^2 = (a + b) (a-b) where a = 8x and b = 11

    Answer is:

    (8x+11) (8x-11)
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