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1 June, 18:54

An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A), and that 21% were both male and between the ages of 18 and 20. What is the probability of choosing a random student who is a female or between the ages of 18 and 20? Assume P (F) = P (not M). Your answer should be given to two decimal places.

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  1. 1 June, 19:51
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    Answer: Our required probability is 0.65.

    Step-by-step explanation:

    Since we have given that

    18-20 Not 18-20 Total

    Male 0.23 0.35 0.58

    Female 0.16 0.26 0.42

    Total 0.39 0.61 1

    P (female or between 18-20) = P (female) + P (18-20) - P (Female and 18-20)

    P (female or between 18-20) = 0.42+0.39-0.16

    P (female or between 18-20) = 0.65

    Hence, our required probability is 0.65.
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