A triangle has three unequal sides. The longest side is 3 in. shorter than twice

the length of the shortest side, and the

middle side length is 4.5 in. longer than

half the longest side. If the perimeter of

the triangle is 48 in., what is the

measure of each side?

Step-by-step explanation:

Let's represent the various sides of the triangle as follows;

Longest side is A

Middle side is B

Shortest side is C

From the question,

A = 2C-3

B = (2C-3) / 2 + 4.5 = C-1.5+4.5 = C+3

Perimeter of a triangle = A+B+C

48In = 2C-3 + C+3 + C

Note that - 3+3 = 0

48 = 2C+C+C

48 = 4C

Divide 48 by the coefficient of C

48/4 = C

C = 12In

Substitute the value of C into the expressions for A and B

A = 2C-3 = (2*12) - 3 = 24-3=21In

B = C+3=12+3=15In

The sides of the triangle are 21in, 15In and 12In respectively