2x^2+x-1=2

What can be x

Answer:Two solutions were found:

x = (2-√20) / 8 = (1-√ 5) / 4 = - 0.309

x = (2+√20) / 8 = (1+√ 5) / 4 = 0.809

Either x = 1 or x = - 3/2

Step-by-step explanation:

= 2X^2 + x - 1 = 2

= 2x^2 + x - 1 - 2 = 0

= 2x^2 + x - 3 = 0

now the above equation has become quadratic equation so we apply the quadratic formula which is:

x = (-b ± √ b^ 2 - 4ac) / 2a

here,

a=2, b=1 and c=-3

putting the values in the formula:

x = (-1 ± √ (1) ^ 2 - 4 (2) (-3)) / 2 (2)

x = (-1 ± √ (1) + 24)) / (4)

x = (-1 ± √ 25) / (4)

x = (-1 ± 5) / (4)

now,

Either: x = (-1 + 5) / (4) or: x = (-1 - 5) / (4)

x = (4) / (4) x = (-6) / (4)

x = 1 x = - 3/2