Cindy has a jar of mixed nuts. There are two pecans, three peanuts, and one cashew in the jar. Cindy grabs two nuts and gives them to her friend, Paul, and he eats them. What is the probability of Paul eating a cashew and a pecan?

A 1/18

B 1/15

C 2/11

D 1/4

Question

Mathematics

Corky

11 May, 07:47

Cindy has a jar of mixed nuts. There are two pecans, three peanuts, and one cashew in the jar. Cindy grabs two nuts and gives them to her friend, Paul, and he eats them. What is the probability of Paul eating a cashew and a pecan?

A 1/18

B 1/15

C 2/11

D 1/4

+5

Answers (1)

Know the Answer?

Jaylin Bean · Answer 1

B 1/15

Step-by-step explanation:

This is non-replacement choosing, so no matter which order is that (cashew-pecan or pecan-cashew) the probability is either

1 / 6 x 2 / 5 or 2 / 6 x 1 / 5 = 2/30 = 1/15

Cindy has a jar of mixed nuts. There are two pecans, three peanuts, and one cashew in the jar. Cindy grabs two nuts and gives them to her friend, Paul, and he eats them. What is the probability of Paul eating a cashew and a pecan?A 1/18B 1/15C 2/11D 1/4

Cindy has a jar of mixed nuts. There are two pecans, three peanuts, and one cashew in the jar. Cindy grabs two nuts and gives them to her friend, Paul, and he eats them. What is the probability of Paul eating a cashew and a pecan?

A 1/18

B 1/15

C 2/11

D 1/4