How to solve y=2x+6 and 2x+y=18 in elimination method?

Answer: x=3; y=10

Step-by-step explanation:

y = 2x+6 ... eqn 1

2x+y=18 ... eqn 2

Substitute y into eqn 2

2x + (2x + 6) = 18

2x + 2x + 6 = 18

4x+6=18

x=18-6/4

*=3

Substitute x=3 in eqn 1 to get the value of y

y = 2 (2) + 6

=4+6

y=10