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7 April, 08:33

Choose the family of distributions that best fits the described situation: You want to model the number of lines of code run until the first 'bug' is detected. The probability a line of code has a bug is 0.003 or 0.3%.

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  1. 7 April, 12:07
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    Answer is : Geometric distribution

    Let X be the number of lines of codes run until the first bug is detected

    That is X is the random variable which is the number of trials needed to get first success. Success here is detection of bug. Success has constant probability in each trail which is p = 0.003. That is before the first success we have X-1 failures with probability (1-0.003)

    The probability mass function of X is

    P (X=x) = (1-p) x-1 p

    P (X=x) = (1-0.003) x-1 * 0.003, x = 1,2, ...

    This distribution is also Negative Binomial distribution

    As geometric distribution is special case of Negative Binomial Distribution

    In Negative Binomial distribution, we have r success (r/geq 1) and the random variable is the number of Bernouli trials needed to get r successes.

    If we put, r = 1, that is number of success is 1

    Then the given situation, that is number of lines code run (X) before the first bug follow negative binomial distribution

    The probability mass function of Negative Binomial distribution is

    P (X=x) = (1-p) x-r pr, x = r, r+1, ...

    The probability mass function of X is

    P (X=x, r=1) = (1-0.003) x-1 * 0.003, x = 1,2, ...
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