At the end of the day a cashier counted 140 quarters and nickels in the register. The coins total 19 dollars. How many coins of each kind was in the register?

80 nickels and 60 quarters.

Step-by-step explanation:

The cashier counted a total of 140 quarters and nickel.

Let the number of nickels=n

Let the number of quarters=q

That means:

n+q=140. (1)

Now, A nickel=5 cents=$0.05

Similarly, 1 Quarter = 25 cents=$0.25

The coins total $19

Therefore:

0.05n+0.25q=19. (2)

We solve the two equations simultaneously.

n+q=140. (1)

0.05n+0.25q=19. (2)

From (1)

n=140-q

Next we substitute n=140-q into equation (2) to solve for q.

0.05 (140-q) + 0.25q=19

Opening the brackets

7-0.05q+0.25q=19

Collecting like terms

-0.05q+0.25q=19-7

0.2q=12

q=60

From Equation (1)

n=140-q

n=140-60=80

Therefore, there were 80 nickels and 60 quarters.