A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. Which

expression would determine the probability that both digits are even?

P (both even) - POM).

P (both even) = 491) 36)

.

P (both even) = (PGP).

5P2

P (both even) = 6) 66).

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A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. Whichexpression would determine the probability that both digits are even?P (both even) - POM).P (both even) = 491) 36).P (both even) = (PGP).5P2P (both even) = 6) 66).

A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. Which

expression would determine the probability that both digits are even?

P (both even) - POM).

P (both even) = 491) 36)

.

P (both even) = (PGP).

5P2

P (both even) = 6) 66).