In a certain game of dice, two fair dice are rolled. If the total of the faces is 4 or 10, you win. If the total is 2, 3, or 11, you lose. In all other cases you roll again. Find the probability that you will roll again.

You answer should be 7/12, or aprox. 0.58 (I could be wrong)

You need to divid the number of outcomes that will satisfy your probability (anything that's not 4,10,2,3, or 11, so there are 7 numbers left) by the total number of outcomes, (12), and that's your answer