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13 January, 05:37

A polynomial has been factored below, but some constants are missing. 2x^3 - 6x^2 - 8x=ax (x+b) (x+c) What are the missing values of a, b, and c?

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Answers (2)
  1. 13 January, 08:30
    0
    Step-by-step explanation:

    hello:

    2x^3 - 6x² - 8x=ax (x+b) (x+c)

    2x^3 - 6x² - 8x = 2x (x²-3x-4)

    but : x²-3x-4 = (x+1) (x-4)

    so : 2x^3 - 6x² - 8x = 2x (x+1) (x-4)

    a=2 and b=1 and c = - 4
  2. 13 January, 08:48
    0
    2x (x - 4) (x + 1). A=2, B=-4, C=1
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