A polynomial has been factored below, but some constants are missing. 2x^3 - 6x^2 - 8x=ax (x+b) (x+c) What are the missing values of a, b, and c?

Question

Mathematics

Mireya Rasmussen

13 January, 05:37

A polynomial has been factored below, but some constants are missing. 2x^3 - 6x^2 - 8x=ax (x+b) (x+c) What are the missing values of a, b, and c?

+4

Answers (2)

Know the Answer?

Arthur Dominguez · Answer 1

Step-by-step explanation:

hello:

2x^3 - 6x² - 8x=ax (x+b) (x+c)

2x^3 - 6x² - 8x = 2x (x²-3x-4)

but : x²-3x-4 = (x+1) (x-4)

so : 2x^3 - 6x² - 8x = 2x (x+1) (x-4)

a=2 and b=1 and c = - 4

Kenna Hawkins · Answer 2

Kenna Hawkins 13 January, 08:48

0

2x (x - 4) (x + 1). A=2, B=-4, C=1