Select the solution for the system of linear equations y=3x+4 and y=x+2

the solutions are

y = 1; x = - 1

Step-by-step explanation:

Given two equations

3x + 4 = y ... (1)

x + 2 = y ... (2)

From equation (2), we make x subject of formula to form a new equation (3) by subtracting 2 from both sides of the equation

x + 2 - 2 = y - 2

x = y - 2 ... (3)

Now we substitute the value of x in equation (3) into equation (1)

3x + 4 = y

3 (y - 2) + 4 = y

3y - 6 + 4 = y

3y - 2 = y

Add 2 to both sides of the equation

3y - 2 + 2 = y + 2

3y = y + 2

Subtract your from both sides

3y - y = y + 2 - y

2y = 2

Divide both sides by 2

2y/2 = 2/2

y = 1

Now we substitute the new value of y = 1 into equation (2)

x + 2 = y

x + 2 = 1

x + 2 - 2 = 1 - 2

x = - 1

( - 1, 1)

Step-by-step explanation:

Given the 2 equations

y = 3x + 4 → (1)

y = x + 2 → (2)

Substitute y = 3x + 4 into (2)

3x + 4 = x + 2 (subtract x from both sides)

2x + 4 = 2 (subtract 4 from both sides)

2x = - 2 (divide both sides by 2)

x = - 1

Substitute x = - 1 into either of the 2 equations and evaluate for y

Substituting x = - 1 into (2)

y = - 1 + 2 = 1

Solution is ( - 1, 1)