A ball is thrown upward and its height is given by s (t) = - 16t^2 + 96t, find the average velocity between t = 1s and t = 3s.

127

Step-by-step explanation:

s (t) = - 16t^2 + 96t = - 16t (t-6)

if t = 1 sec

-16t (t-6) = - 16x1 (1-6) = - 16 (-5) = 90

if t = 3sec

-16x3 (3-6) = - 48 (-3) = 144

the average velocity between 1 sec and 3 secs = (90+144) / 2 = 254/2 = 127