Dimensions of a rectangle whose length is 8 more than twice it's width and has a perimeter of 40 cm.

Width = 4 cm

Length = 16 cm

Step-by-step explanation:

We are given;

Perimeter = 40 cm Assuming the width is x Then, length is 2x + 8 (8 more than twice the width)

We are required to determine the dimensions of the rectangle;

We need to know that the perimeter of the rectangle is given by; Perimeter = 2 (length + width)

In this case;

2 (2x + 8 + x) = 40

2 (3x + 8) = 40

6x + 16 = 40

6x = 24

x = 4

Thus; the dimensions of the rectangle are;

Width = 4 cm, and

Length = 16 cm