If the first term of an arithmetic sequence is 4 and the difference between con-

secutive terms is 5, what is the second term? The third term? The twelfth? The

eightieth? The nth?

Second term=9

Third term=14

Twelfth term=59

Eightieth term=399

nth term=-1+5n

Step-by-step explanation:

First term=a=4

Common difference=d=5

using the formula

Tn=a + d x (n-1)

Second term=4 + 5 x (2-1)

Second term=4 + 5 x 1

Second term=4 + 5

Second term=9

3rd term=4+5x (3-1)

3rd term=4+5x2

3rd term=4+10

3rd term=14

12th term=4+5x (12-1)

12th term=4+5x11

12th term=4+55

12th term=59

80th term=4+5x (80-1)

80th term=4+5x79

80th term=4+395

80th term=399

nth term=4+5 (n-1)

nth term=4+5n-5

nth term=4-5+5n

nth term=-1+5n