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15 February, 19:36

How do I write a function rule for the area of a rectangle whose length is 4in. more than its width. What is the area of the rectangle when its width is 8in.?

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  1. 15 February, 20:09
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    Let the width be w, then length = w + 4

    Area = length x width = w (w + 4) = w^2 + 4w

    f (w) = w^2 + 4w

    for w = 8 in

    Area = (8) ^2 + 4 (8) = 64 + 32 = 96 in^2
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