Suppose A and B are mutually exclusive events, and that P (B) = 0.03 and P (A OR B) = 0.52. Find P (A)

P (A) = 0.49

Step-by-step explanation:

Given:

A and B are mutually exclusive events.

P (B) = 0.03

P (A or B) = 0.52

If two events A and B are mutually exclusive events, then there are no elements common in both the events. So, the probability of their intersection is 0.

Now, as per probability addition theorem:

P (A or B) = P (A) + P (B) + P (A and B)

For mutually exclusive events, P (A and B) = 0. So,

P (A or B) = P (A) + P (B) + 0

P (A or B) = P (A) + P (B)

Plug in the given values and solve for P (A). This gives,

0.52 = P (A) + 0.03

P (A) = 0.52 - 0.03

P (A) = 0.49

Therefore, the probability of occurrence of event A is P (A) = 0.49.