 Mathematics
4 June, 11:50

# Sleepy is eight years younger than scoopy. Doc is 5 times as old as scoopy. The sum of their age is 55. How old are each of them? This is the exact problem from worksheet.

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Answers (1)
1. 4 June, 13:44
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The age of Sleepy is 1.

Then the age of Scoopy is 9.

The age of Doc would be 45.

Step-by-step explanation:

We have to find the ages of all the three people based on the given equations.

Let the age of Sleepy be x. Since Scoopy is 8 years older than Sleepy, the age of Scoopy would be (x+8).

Also Doc is 5 times as old as Scoopy so his age is 5 (x+8).

Now the sum of the ages of all three is 55.

Writing equation for this,

x + x + 8 + 5 (x+8) = 55

7x + 48 = 55

7x = 7

x = 1

So the age of Sleepy is 1. Then the age of Scoopy is 9.

The age of Doc would be 45.
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