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4 June, 11:50

Sleepy is eight years younger than scoopy. Doc is 5 times as old as scoopy. The sum of their age is 55. How old are each of them? This is the exact problem from worksheet.

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  1. 4 June, 13:44
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    The age of Sleepy is 1.

    Then the age of Scoopy is 9.

    The age of Doc would be 45.

    Step-by-step explanation:

    We have to find the ages of all the three people based on the given equations.

    Let the age of Sleepy be x. Since Scoopy is 8 years older than Sleepy, the age of Scoopy would be (x+8).

    Also Doc is 5 times as old as Scoopy so his age is 5 (x+8).

    Now the sum of the ages of all three is 55.

    Writing equation for this,

    x + x + 8 + 5 (x+8) = 55

    7x + 48 = 55

    7x = 7

    x = 1

    So the age of Sleepy is 1. Then the age of Scoopy is 9.

    The age of Doc would be 45.
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