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9 July, 07:12

Yuto and Lian are at train stations 1,880 kilometers apart. Yuto boards a train heading east at an average speed of 220

kilometers per hour. At the same time, Lian boards a train heading west on a parallel track at an average speed of 250

kilometers per hour. How far has Lian traveled when the two trains pass each other?

Time

(h)

Rate

(km/h)

220

250

Distance

(km)

220t

250t

Yuto

Lian

470 kilometers

880 kilometers

940 kilometers

1,000 kilometers

+3
Answers (1)
  1. 9 July, 09:40
    0
    1,000 km

    Step-by-step explanation:

    Assume that when two train pass each other, Lian has traveled x (km)

    => The time Lian has traveled when two trains pass each other is:

    Time = Distance / Rate = x / 250 (hour)

    As Lian and Yuto travelled from the two opposite train stations and the train stations are 1,880 km apart

    => When two train pass each other, Yuto has traveled 1,880 - x (km)

    => The time Yuto has traveled when two trains pass each other is:

    Time = Distance / Rate = (1,880 - x) / 220 (hour)

    As Lian and Yuto board at the same time, so that when two trains pass each other, the time both of them have traveled is equal

    => x / 250 = (1,880 - x) / 220

    => 220x = 250 x (1,880 - x)

    => 220x = 470,000 - 250x

    => 470x = 470,000

    => x = 1,000

    So that, when two train pass each other, Lian has traveled x = 1,000 km
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