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25 April, 14:23

A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is $5786 dollars. How much did he invest at each rate?

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  1. 25 April, 17:27
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    at 10 % amount will be $26300

    at 6 % amount will be $52600

    Step-by-step explanation:

    given data

    rate r1 = 6%

    rate r2 = 10 %

    interest = $5786

    to find out

    How much he invest

    solution

    we know man save at rate 6% and 10 %

    and get interest $5786

    so we consider invest amount at 10% = x

    and so invest amount at 6% = 2x

    so interest equation will be

    0.10 (x) + 0.06 (2x) = 5786

    0.10 x + 0.12x = 5786

    0.22 x = 5786

    x = 26300

    so

    at 10 % amount will be $26300

    at 6 % amount will be $52600
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