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7 July, 11:09

Small scooters cost £80 and large scooters cost £130. A school buys few scooters for the playground for £1000. How many of the smaller and larger scooter did they buy?

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  1. 7 July, 14:36
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    Small scooters = 6

    Large scooters = 4

    Step-by-step explanation:

    Let S represents small scooter and L represents large scooter

    The cost of a small scooter is £80

    Mathematically, the cost of S number of small scooters is

    80S

    The cost of a large scooter is £130

    Mathematically, the cost of L number of large scooters is

    130L

    The total amount spent on both scooters is £1000

    Mathematically,

    80S + 130L = 1000

    So we have 2 unknowns and only 1 equation. Therefore, we have use trial and error method.

    Trial and Error Method:

    80S + 130L = 1000

    80S = 1000 - 130L

    S = (1000 - 130L) / 80

    Let's suppose they bought 1 large scooter

    S = (1000 - 130 (1)) / 80

    S = 10.875

    Number of scooters cannot be in fraction so 1 doesn't work

    Let's suppose they bought 2 large scooter s

    S = (1000 - 130 (2)) / 80

    S = 9.25

    Number of scooters cannot be in fraction so 2 doesn't work

    Let's suppose they bought 3 large scooter s

    S = (1000 - 130 (3)) / 80

    S = 7.625

    Number of scooters cannot be in fraction so 3 doesn't work

    Let's suppose they bought 4 large scooters

    S = (1000 - 130 (4)) / 80

    S = 6

    So that means they bought 6 small scooters and 4 large scooters.

    Similarly, other combinations for scooters don't work since they yield either fractional value or negative value which cannot be correct.

    Therefore, the only possible combination of small and large scooters is

    6 Small scooters

    4 Large scooters

    Verification:

    80S + 130L = 1000

    80 (6) + 130 (4) = 1000

    480 + 520 = 1000

    1000 = 1000 (satisfied)
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