What are the solutions to 2x^2+7y=4? Select all that apply.

1/2

4

-1/2

-4

7

-7

x = - 1/2, 4

Step-by-step explanation:

1) If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

2x+1=0

x-4=0

2) Set the first factor equal to 0.

2x+1=0

3) Subtract 1 from both sides of the equation.

2x=-1

4) Divide each term by 2 and simplify.

2x/2 = - 1/2

5) Cancel the common factor of 2.

x = - 1/2

6) Move the negative in front of the fraction.

x = - 1/2

7) Set the next factor equal to 0 and solve.

x=4

8) The final solution is all the values that make

(2x+1) (x-4) = 0 true.

9) x = - 1/2, 4