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10 January, 16:14

Complete the square and graph: 4y^2+x+8y+1=0

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  1. 10 January, 16:21
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    The answer to your question is:

    Step-by-step explanation:

    4y² + x + 8y + 1 = 0

    4y² + 8y = - x - 1

    4 (y² + 8y) = - x - 1

    (y² + 2y) = - 1/4 x - 1/4

    (y² + 2y + 1) = - 1/4 x - 1/4 + 1

    (y² + 2y + 1) = - 1/4 x + 3/4

    (y + 1) ² = - 1/4 (x - 3)

    Vertix (3, - 1)

    It's a parabola that opens to the left.
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