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25 February, 00:46

Two cyclists, 90 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other.

If they meet 3 hr later, at what average speed is each cyclist traveling?

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  1. 25 February, 02:19
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    Speed of cyclist 1 = 10 mile per hourSpeed of cyclist 2 = 20 mile per hour

    Step-by-step explanation:

    Distance between cyclists = 90 miles

    Let v be the speed of one cyclist, speed of other cyclist is twice the speed of first cyclist.

    Speed of second cyclist = 2 x v

    Time taken by them to meet = 3 hr

    Since they are moving towards each other, relative velocity is given by

    Relative velocity = v + 2v = 3v

    We have

    Distance = Time x Velocity

    90 = 3 x 3 v

    9v = 90

    v = 10 mile per hour

    Speed of cyclist 1 = v = 10 mile per hour

    Speed of cyclist 2 = 2v = 20 mile per hour
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