A hockey season ticket holder pays 72.48 for her tickets plus 6.00 for a program each game each game a second person pays 18.08 for a ticket to every game but doesnt buy programs in how many games will they have paid the same amount

If I understand the question correct, the hockey season ticket holder paid $72.48 for all of the tickets at once, and then $6.00 for each game thereafter. The second person pays $18.08 for a ticket per game.

So then let g = the number of games. The problem can be written as a system of equations:

Person 1 = 72.48 + 6g

Person 2 = 18.08g

We are looking for when the number of games for both are the same. To do this, just set them equal to each other and solve for g.

72.48 + 6g = 18.08g

Subtract 6g:

72.48 = 12.08g

Divide by 12.08:

g = 6

So after 6 games, the two would have paid the same price.