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27 November, 15:20

Y = - 3x + 5 y = mx + b Which values of m and b will create a system of linear equations with no solution? m = - 3 and b = - 3 m = 5 and b = - 3 m = 3 and b = 5 m = - 3 and b = 5

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  1. 27 November, 15:55
    0
    (A) m = - 3 and b = - 3

    Step-by-step explanation:

    If m=-3 and b=-3

    The system of linear equations:

    y = - 3x + 5

    y = mx + b

    Becomes

    y = - 3x + 5 ... (i)

    y = - 3x - 3 ... (ii)

    Notice that 5 is added to - 3x in (i) and - 3 is added to - 3x in (ii) and both equals y. This is impossible. Thus the system has no solution.
  2. 27 November, 16:31
    0
    m = - 3 and b = - 3

    Step-by-step explanation:

    y = - 3x + 5 (1)

    A system has no solution when we have an inconsistency. The case where an inconsistency remains is when m = - 3 and b = - 5. In the following way:

    y = - 3x - 3 (2)

    if I multiply by - 1 (2) and the add to (1). We have left

    y = - 3x + 5

    -y = 3x + 3

    0 = 0 + 8

    And 0 is not equal to 8, therefore it is inconsistent.
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