Given f (x) = 3x^2+2x-10 and g (x) = 3x-3 If g (f (x)) = 2

f (x) = 3x^2+2x-10 if x=2

f (x) = 3 (2) ^2+2 (2) - 10

f (x) = 3 (4) + 2 (2) - 10

f (x) = 12+4-10

f (x) = 16-10

f (x) = 6

g (x) = 3x-3 if g (x) = 2

g (x) = 3 (2) - 3

g (x) = 6-3 = 3

Step-by-step explanation:

f (x)

replace x by 2 do exponent distribute the brackets do addition and subtraction

g (x)

replace x by 2 distribute the bracket do subtraction

5/3 and - 7/3

Step-by-step explanation:

Given f (x) = 3x²+2x-10 and g (x) = 3x-3

g (f (x)) = 2 : g (3x²+2x-10) = 2

replace x with : 3x²+2x-10 in g (x)

3 (3x²+2x-10) - 3 = 2

9x²+6x - 35 = 0

the discriminant delta = b² - 4ac a = 9 and b=6 and c = - 35

delta = 6² - 4 (9) (-35) = 1296 = 36²

x1 = (-6+36) / 18 = 30/18 = 5/3

x2 = (-6-36) 18 = - 42/18 = - 7/3