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27 October, 11:39

Set up a system of equations needed to solve each probler

11. You have 42 coins valued at $3.00. Some of

the coins are dimes and some are quarters. Find the

number of each you have.

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Answers (1)
  1. 27 October, 15:25
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    This is not a solvable question, since the least amount of money you can have with this combination is $4.20.

    Step-by-step explanation:

    Let q = quarters

    Let d = dimes

    Equation: 0.1d + 0.25q = 3.00

    Maximum amount of dimes: 0.1d * 42 = 4.2d
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