A school gym is divided for a fair by bisecting its width and its length. Each half of the length is then bisected, forming 8 sections in all. What are the dimensions and area of each section?

Dimensions will be

New Length = x/16 units

New width = y/2 units

Area=xy/32 square units

Step-by-step explanation:

Lets assume the dimensions of the school gym to be;

Length = x

width = y

Length and width are first bisected for a fair. This means by a half

Length will be = x/2

Width will be = y/2

Then the length is divided to form 8 sections that are equal, which will;

(x/2) : 8

x/2 * 1/8 = x/16 units

New length = x/16 units in dimension

New width will be y/2 units in dimension

Area of each section will be;

length by width

(x/16) * (y/2)

=xy/32 square units