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3 March, 16:48

A rectangle is 12 ft long and 5 feet wide. If the length of the rectangle is increased by 25% and the width is decreased by 20%, what is the change in area of the rectangle?

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Answers (2)
  1. 3 March, 19:35
    0
    Answer:There is no change in the area of the rectangle

    Step-by-step explanation: If the rectangle is 12 ft long and 5 ft wide, then the area becomes,

    Area = L x W

    Area = 12 x 5

    Area = 60 ft^2

    However, if the length is increased by 25%, then the new length becomes

    Increase = 12 x (25/100)

    Increase = 12 x (1/4)

    Increase = 3 ft

    So the new length would be 12 + 3 and that equals 15 ft.

    Also if the width is decreased by 20%, the new width becomes

    Decrease = 5 x (20/100)

    Decrease = 5 x (1/5)

    Decrease = 1 ft

    So the new width would be 5 - 1 and that equals 4 ft

    Hence with the new dimensions as

    L = 15 and W = 4

    The new area becomes

    Area = 15 x 4

    Area = 60 ft^2

    Thus the new area is not different from the previous one. There is no change.
  2. 3 March, 19:40
    0
    12ft long and 5ft wide.

    25% of 12 = 3.

    Increase in 25%

    12 + 3 = 15.

    20% of 5 = 1.

    Decrease in 20%

    5 - 1 = 4.

    Old Area: 12*5 = 48

    New Area: 15*4=60.

    So bigger.
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