A baseball team played 130 games in a season. If it won sixteen more games

twice as many games as it lost, how many wins and losses did the team have?

The team has 92 wins and 38 losses.

Step-by-step explanation:

In a season 130 games are played by a baseball team.

Let us assume that the team wins x games and losses y games.

Therefore, we can write, x + y=130 ... (1)

It is given that if the team won sixteen more games twice as many games as it lost.

So, we can conclude that x = 2y+16 ... (2)

Hence, solving equations (1) and (2) we get, (2y+16) + y = 130

⇒ 3y = 114

⇒ y = 38

And from equation (2), x = 2*38 + 16 = 92

Therefore, the team has 92 wins and 38 losses. (Answer)