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20 March, 06:21

Solve the equation 4x^2+49=0

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  1. 20 March, 09:36
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    x=7/2i, - 7/2i

    Step-by-step explanation:

    4x^2+49=0

    4 (x^2+49/4) = 0

    x^2+49/4=0/4

    x^2+49/4=0

    x^2=0-49/4

    x^2=-49/4

    take the square root of - 49/4, you'll get imaginary numbers because of the negative sign.

    x=7/2i, - 7/2i
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