Solve the equation 4x^2+49=0

x=7/2i, - 7/2i

Step-by-step explanation:

4x^2+49=0

4 (x^2+49/4) = 0

x^2+49/4=0/4

x^2+49/4=0

x^2=0-49/4

x^2=-49/4

take the square root of - 49/4, you'll get imaginary numbers because of the negative sign.

x=7/2i, - 7/2i