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22 January, 12:53

I'm looking at the top at 79.9 angle. I'm 100ft away. What's the height of the building?

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Answers (2)
  1. 22 January, 13:48
    0
    To solve this, notice that you have the angle component (I will call this a) and the x-component (the distance of you from the building) of a trig formula, and you are looking for the y-component. We will use the tangent formula, since this incorporates the angle, x, and y components.

    1. Write the formula

    tan (a) = y : x

    2. Rewrite to include the known values.

    tan (79.9) = y : 100

    3. Solve for the unknown variable, y.

    tan (79.9) * 100 = y : 100 * 100

    tan (79.9) * 100 = y

    4. A fancy step that I call the "flip flop."

    y = tan (79.9) * 100

    5. Use a calculator to find the value (make sure the calculator is in "degree" and not "radians" mode).

    y = 561.3968

    6. Round the number as is appropriate for this problem.

    Have a great day!
  2. 22 January, 15:29
    0
    So this is a trig problem

    so you have a right triangle

    base=100 ft

    from wher you are standing, it is a 79.9 angle to the top

    we want to find the height of the tower or the opposite side

    the base is the adjacent side so you are looking for o/a or tan (79.9) since you know one of the sides so therefor

    tan (79.9) = h/100

    evaluate tan (79.9)

    tan (79.9) = 5.61396

    5.61396=h/100

    multiply both sides by 100

    561.396=h

    round to tenths place

    561.4

    the height=561.4 ft
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