One leg of a right triangle has a length of 3. The other sides have lengths that are consecutive integers. Find these lengths.

Therefore other two sides of the triangle are 4 and 5.

Step-by-step explanation:

Given one leg of a right triangle has a length of 3

Let other sides of the triangle be x and x+1 [ since they are consecutive]

According to the problem,

3²+x² = (x+1) ²

⇔9 + x²=x²+2x+1

⇔2x+1=9

⇔2x=9-1

⇔2x=8

⇔x=4

Therefore other two sides of the triangle are 4 and 5.