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27 April, 16:57

Suppose an individual is randomly selected from the population of all adult males living in the United States. Let A be the event that the selected individual is over 6 ft in height, and let B be the event that the selected individual is a professional basketball player ... Which is larger, P (A|B) or P (B|A) ?.

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  1. 27 April, 18:28
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    P (A|B)

    P (A|B) is expected to be bigger because most basketball players are over 6ft but only a few tall people (6ft + ) are basketball players.

    Step-by-step explanation:

    P (A|B) means probability that the selected individual is over 6 ft given that he plays basketball

    P (B|A) means the probability that the selected individual plays basketball, given that he is over 6ft.

    P (A|B) is expected to be bigger because most basketball players are over 6ft but only a few tall people (6ft + ) are basketball players.

    P (A) = Probability that the selected individual is over 6 ft in height; normally in a total population of humans, this would be a very small figure, (there are way more people 6ft and under in the world than there are people taller than 6ft)

    P (A) is approximated to be 0.05

    P (B) is the probability that the selected individual is a professional basketball player. It is even rarer to get a professional basketball player when all the population is considered. P (B) is approximated to be 0.0005

    Mathematically,

    P (A|B) = P (A n B) / P (B)

    P (B|A) = P (A n B) / P (A)

    P (A|B) = P (A n B) / 0.0005 = 2000 * P (A n B)

    P (B|A) = P (A n B) / 0.05 = 20 * P (A n B)

    Since P (A n B) is equal for the two cases, P (A|B) > P (B|A)
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