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7 May, 19:50

At one vehicle inspection station, 13 of 52 trucks and 11 of 88 cars failed the emissions test. Assuming these vehicles were representative of the cars and trucks in that area, what is the standard error of the difference in the percentages of all cars and trucks that are not in compliance with air quality regulations?

A).025

B).032

C).049

D).070

E).095

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  1. 7 May, 22:19
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    Answer: The standard error of the difference in the percentages of all cars and trucks that are not in compliance with air quality regulations is 0.066 approximately 0.070

    Therefore the answer is (D) 0.070

    Step-by-step explanation:

    Given that 13 of 52 trucks and 11 of 88 cars failed the emissions test.

    p1 = 13 of 52 trucks

    p2 = 11 of 88 cars

    Solution:

    The standard error (SE) of the sampling distribution difference between two proportions is given by;

    SE = √{p (1-p) (1/n1 + 1/n2) }

    Where p is termed pooled sample

    n1 is the size of sample 1, and

    n2 is the size of sample 2.

    p = (p1*n1 + p2*n2) / (n1 + n2)

    p1 = 13/52 = 0.25

    p2 = 11/88 = 0.125

    n1 = 52

    n2 = 88

    p = (0.25*52 + 0.125*88) / (52 + 88)

    p = 0.1714

    SE = √{0.1714 (1-0.1714) (1/52 + 1/88) }

    SE = √0.0044

    SE = 0.066 the standard error
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