A fruit stand owner has 90 apples and 72 oranges. He wants to make the greatest number possible of identical bags with a

combination of apples and oranges without any fruit leftover. How many apples are in each bag?

A)

4

E)

18

Question

Mathematics

Guest

24 February, 02:50

A fruit stand owner has 90 apples and 72 oranges. He wants to make the greatest number possible of identical bags with a

combination of apples and oranges without any fruit leftover. How many apples are in each bag?

A)

4

E)

18

+2

Answers (2)

Know the Answer?

Jamie Boone · Answer 1

18 bags

with 90/18 = 5 apples

and 72/18 = 4 oranges

in each bag

Kaden Graves · Answer 2

5

Step-by-step explanation:

The greatest common Divisor of 90 and 72 is 18

Then

the number of apples in each bag = 90:18 = 5

the number of oranges in each bag = 72:18=4

A fruit stand owner has 90 apples and 72 oranges. He wants to make the greatest number possible of identical bags with acombination of apples and oranges without any fruit leftover. How many apples are in each bag?A)4E)18

A fruit stand owner has 90 apples and 72 oranges. He wants to make the greatest number possible of identical bags with a

combination of apples and oranges without any fruit leftover. How many apples are in each bag?

A)

4

E)

18