Ask Question
6 January, 18:58

The length of a rectangle is 4 meters less than 3 times it's width. If the perimeter of the rectangle is at most 48 meters, find the greatest possible width of the rectangle

+3
Answers (1)
  1. 6 January, 20:05
    0
    7

    Step-by-step explanation:

    Think about it visually. 3x-4 is the length and x is the width. Since a rectangle has 2 parralel and equal sides, it's just double those. The equation is 8x-8=48. 48 is the total as given in the problem.

    8x-8=48

    8x=56

    x=7

    The width is 7.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The length of a rectangle is 4 meters less than 3 times it's width. If the perimeter of the rectangle is at most 48 meters, find the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers